FastFieldSolvers Forum
FastFieldSolvers Forum
Home | Profile | Register | Active Topics | Members | Search | FAQ
Username:
 Password:
Save Password
 All Forums
 FastFieldSolvers
 FastHenry2
 Mutual inductance		  New Topic  Reply to Topic
 Printer Friendly
Author Previous Topic Topic Next Topic  

kislay1947

India
4 Posts
Posted - Oct 22 2011 :  11:43:02  Show Profile  Reply with Quote
Dear all!!


I have written this code.After running through Fasthenry I got impedance matrix as :
Freq = 10000
Row 0: 21.077+0.00418531j 6.9843+0.0041512j
Row 1: 6.98431+0.0041512j 6.98452+0.0041512j


Are the values correct. Is .0041512 the correct mutual inductance??
.default z=0 sigma=5.8e4 nhinc =5 nwinc=5

N1_1 x=0 y=0
N1_2 x=600 y=0
N1_3 x=600 y=600
N1_4 x=0 y=600
N1_5 x=0 y=1
N1_6 x=599 y=1
N1_7 x=599 y=599
N1_8 x=1 y=599
N1_9 x=1 y=2
N2_10 x=0 y=1 z=2
E1_1 N1_1 N1_2 w=.1 h=.1
E1_2 N1_2 N1_3 w=.1 h=.1
E1_3 N1_3 N1_4 w=.1 h=.1
E1_4 N1_4 N1_5 w=.1 h=.1
E1_5 N1_5 N1_6 w=.1 h=.1
E1_6 N1_6 N1_7 w=.1 h=.1
E1_7 N1_8 N1_9 w=.2 h=.2

N2_1 x=0 y=0 z=50
N2_2 x=600 y=0 z=50
N2_3 x=600 y=600 z=50
N2_4 x=0 y=600 z=50
N2_5 x=0 y=1 z=50
E2_1 N2_1 N2_2 w=.1 h=.1
E2_2 N2_2 N2_3 w=.1 h=.1
E2_3 N2_3 N2_4 w=.1 h=.1
E2_4 N2_4 N2_5 w=.1 h=.1
.equiv N1_1 N2_1
.equiv N1_9 N2_5
.external N1_1 N1_9
.external N2_1 N2_5
.freq fmin=1e1 fmax=1e9 ndec=1
.end


kislay

RonJ103

USA
3 Posts
Posted - Oct 26 2011 :  19:40:46  Show Profile  Reply with Quote
I get an error from Fast Henry when trying to run your code. It seems that your .equiv statements create a loop. Are you sure you are running the code that you posted?
Go to Top of Page
  Previous Topic Topic Next Topic  
 New Topic  Reply to Topic
 Printer Friendly
Jump To:
FastFieldSolvers Forum © 2020 FastFieldSolvers S.R.L. Go To Top Of Page
Powered By: Snitz Forums 2000 Version 3.4.06